advance math mcq pdf Model Questions & Answers, Practice Test for ibps rrb so officer sclae 2 3 single exam 2024
ibps rrb so officer sclae 2 3 single exam 2024 SYLLABUS WISE SUBJECTS MCQs
Number System
Lcm & Hcf
Ratio & Proportion
Percentage
Time & Work
Mensuration
Advance Math
Trigonometric Ratios & Identities
Average
Profit & Loss
The number of three digit numbers having only two consecutive digits identical is
Answer: (a)
When 0 is the repeated digit like
100, 200, ...., 9 in number
When 0 occurs only once like
110, 220, ....., 9 in number
When 0 does not occur like
112, 211, ....., 2 × (8 × 9) = 144 in number.
Hence, total = 9 + 9 + 144 = 162.
Two series of a question booklets for an aptitude test are to be given to twelve students. In how many ways can the students be placed in two rows of six each so that there should be no identical series side by side and that the students sitting one behind the other should have the same series ?
Answer: (a)
Six students can be arranged in a row is 6! ways.
Another six students can be further arranged in 6! ways.
Hence, total number of ways = 6! × 6!
Note : Do not get confused with the two type of booklets. The booklets can be distributed in 2 ways.
Both these arrangements will be part of the permutation of students arrangement.
Atul can hit a target 3 times in 6 shots, Bhola can hit the target 2 times in 6 shots and Chandra can hit the 4 times in 4 shots. What is the probability that at least 2 shots (out of 1 shot taken by each one of them) hit the target ?
Answer: (a)
Chandra hits the target 4 times in 4 shots. Hence, he hits the target definitely.
The required probability, therefore, is given by.
P(both Atul and Bhola hit) + P(Atul hits, Bhola does not hit) + P(Atul does not hit, Bhola hits)
= $3/6 × 2/6 + 3/6 × 4/6 + 3/6 × 2/6$
= $1/6 + 1/3 + 1/6 = 4/6 = 2/3$
A group of 630 children is seated in rows for a group photo session. Each row contains three less children than the row in front of it. Which one of the following number of rows is not possible ?
Answer: (d)
Let no. of column = x, no. of rows = y
∴ xy = 630 – [3 × 1 + 3 × 2 + ......... + 3 × (y – 1)]
= 630 – 3 [1 + 2 + ........ + (y – 1)]
xy = 630 – ${3(y - 1) y}/2$
(a) If y = 3, then 3x = 630 – 9⇒ x = ${621}/3$ = 207
(b) If y = 4, then 4x = 630 – 18⇒ x = ${612}/4$ = 153
(c) If y = 5, then 5x = 630 – 30⇒ x = ${600}/5$ = 120
The number of ways in which 6 men and 5 women can dine at a round table if no two women are to sit together is given by
Answer: (a)
No. of ways in which 6 men can be arranged at a round table = (6 - 1)!
Now women can be arranged in 6! ways.
Total Number of ways = 6! × 5!
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